This is an optimization for processing pipeline, we discussed a
problem in issue #5229: clients may be paused if we apply `CLIENT
PAUSE` command, and then querybuf may grow too large, the cost of
memmove in sdsrange after parsing a completed command will be
horrible. The optimization is that parsing all commands in queyrbuf
, after that we can just call sdsrange only once.
This is an optimization for processing pipeline, we discussed a
problem in issue #5229: clients may be paused if we apply `CLIENT
PAUSE` command, and then querybuf may grow too large, the cost of
memmove in sdsrange after parsing a completed command will be
horrible. The optimization is that parsing all commands in queyrbuf
, after that we can just call sdsrange only once.
This is an optimization for processing pipeline, we discussed a
problem in issue #5229: clients may be paused if we apply `CLIENT
PAUSE` command, and then querybuf may grow too large, the cost of
memmove in sdsrange after parsing a completed command will be
horrible. The optimization is that parsing all commands in queyrbuf
, after that we can just call sdsrange only once.
When the element new score is the same of prev/next node, the
lexicographical order kicks in, so we can safely update the node in
place only when the new score is strictly between the adjacent nodes
but never equal to one of them.
Technically speaking we could do extra checks to make sure that even if the
score is the same as one of the adjacent nodes, we can still update on
place, but this rarely happens, so probably not a good deal to make it
more complex.
Related to #5179.
When the element new score is the same of prev/next node, the
lexicographical order kicks in, so we can safely update the node in
place only when the new score is strictly between the adjacent nodes
but never equal to one of them.
Technically speaking we could do extra checks to make sure that even if the
score is the same as one of the adjacent nodes, we can still update on
place, but this rarely happens, so probably not a good deal to make it
more complex.
Related to #5179.
When the element new score is the same of prev/next node, the
lexicographical order kicks in, so we can safely update the node in
place only when the new score is strictly between the adjacent nodes
but never equal to one of them.
Technically speaking we could do extra checks to make sure that even if the
score is the same as one of the adjacent nodes, we can still update on
place, but this rarely happens, so probably not a good deal to make it
more complex.
Related to #5179.
